Defining and Instantiating Structs
Structs are similar to tuples, discussed in the Data Types section, in that both hold multiple related values. Like tuples, the pieces of a struct can be different types. Unlike with tuples, in a struct you’ll name each piece of data so it’s clear what the values mean. Adding these names means that structs are more flexible than tuples: you don’t have to rely on the order of the data to specify or access the values of an instance.
To define a struct, we enter the keyword struct
and name the entire struct. A struct’s name should describe the significance of the pieces of data being grouped together. Then, inside curly brackets, we define the names and types of the pieces of data, which we call fields. For example, Listing 5-1 shows a struct that stores information about a user account.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
To use a struct after we’ve defined it, we create an instance of that struct by specifying concrete values for each of the fields. We create an instance by stating the name of the struct and then add curly brackets containing key: value pairs, where the keys are the names of the fields and the values are the data we want to store in those fields. We don’t have to specify the fields in the same order in which we declared them in the struct. In other words, the struct definition is like a general template for the type, and instances fill in that template with particular data to create values of the type.
For example, we can declare two particular users as shown in Listing 5-2.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
let user1 = User {
active: true, username: "someusername123", email: "someone@example.com", sign_in_count: 1
};
let user2 = User {
sign_in_count: 1, username: "someusername123", active: true, email: "someone@example.com"
};
}
To get a specific value from a struct, we use dot notation. For example, to access user1
's email address, we use user1.email
. If the instance is mutable, we can change a value by using the dot notation and assigning into a particular field. Listing 5-3 shows how to change the value in the email
field of a mutable User
instance.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
let mut user1 = User {
active: true, username: "someusername123", email: "someone@example.com", sign_in_count: 1
};
user1.email = "anotheremail@example.com";
}
fn build_user(email: ByteArray, username: ByteArray) -> User {
User { active: true, username: username, email: email, sign_in_count: 1, }
}
fn build_user_short(email: ByteArray, username: ByteArray) -> User {
User { active: true, username, email, sign_in_count: 1, }
}
Note that the entire instance must be mutable; Cairo doesn’t allow us to mark only certain fields as mutable.
As with any expression, we can construct a new instance of the struct as the last expression in the function body to implicitly return that new instance.
Listing 5-4 shows a build_user
function that returns a User
instance with the given email and username. The active
field gets the value of true
, and the sign_in_count
gets a value of 1
.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
let mut user1 = User {
active: true, username: "someusername123", email: "someone@example.com", sign_in_count: 1
};
user1.email = "anotheremail@example.com";
}
fn build_user(email: ByteArray, username: ByteArray) -> User {
User { active: true, username: username, email: email, sign_in_count: 1, }
}
fn build_user_short(email: ByteArray, username: ByteArray) -> User {
User { active: true, username, email, sign_in_count: 1, }
}
It makes sense to name the function parameters with the same name as the struct fields, but having to repeat the email
and username
field names and variables is a bit tedious. If the struct had more fields, repeating each name would get even more annoying. Luckily, there’s a convenient shorthand!
Using the Field Init Shorthand
Because the parameter names and the struct field names are exactly the same in Listing 5-4, we can use the field init shorthand syntax to rewrite build_user
so it behaves exactly the same but doesn’t have the repetition of username
and email
, as shown in Listing 5-5.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
let mut user1 = User {
active: true, username: "someusername123", email: "someone@example.com", sign_in_count: 1
};
user1.email = "anotheremail@example.com";
}
fn build_user(email: ByteArray, username: ByteArray) -> User {
User { active: true, username: username, email: email, sign_in_count: 1, }
}
fn build_user_short(email: ByteArray, username: ByteArray) -> User {
User { active: true, username, email, sign_in_count: 1, }
}
Here, we’re creating a new instance of the User
struct, which has a field named email
. We want to set the email
field’s value to the value in the email
parameter of the build_user
function. Because the email
field and the email
parameter have the same name, we only need to write email
rather than email: email
.
Creating Instances from Other Instances with Struct Update Syntax
It’s often useful to create a new instance of a struct that includes most of the values from another instance, but changes some. You can do this using struct update syntax.
First, in Listing 5-6 we show how to create a new User
instance in user2
regularly, without the update syntax. We set a new value for email
but
otherwise use the same values from user1
that we created in Listing 5-2.
Filename: src/lib.cairo
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
// --snip--
let user1 = User {
email: "someone@example.com", username: "someusername123", active: true, sign_in_count: 1,
};
let user2 = User {
active: user1.active,
username: user1.username,
email: "another@example.com",
sign_in_count: user1.sign_in_count,
};
}
Using struct update syntax, we can achieve the same effect with less code, as
shown in Listing 5-7. The syntax ..
specifies that the remaining fields not
explicitly set should have the same value as the fields in the given instance.
Filename: src/lib.cairo
use core::byte_array;
#[derive(Drop)]
struct User {
active: bool,
username: ByteArray,
email: ByteArray,
sign_in_count: u64,
}
fn main() {
// --snip--
let user1 = User {
email: "someone@example.com", username: "someusername123", active: true, sign_in_count: 1,
};
let user2 = User { email: "another@example.com", ..user1 };
}
The code in Listing 5-7 also creates an instance of user2
that has a
different value for email
but has the same values for the username
,
active
, and sign_in_count
fields as user1
. The ..user1
part must come last
to specify that any remaining fields should get their values from the
corresponding fields in user1
, but we can choose to specify values for as
many fields as we want in any order, regardless of the order of the fields in
the struct’s definition.
Note that the struct update syntax uses =
like an assignment; this is because it moves the data,
just as we saw in the "Moving Values" section. In this example, we can no
longer use user1
as a whole after creating user2
because the ByteArray
in the
username
field of user1
was moved into user2
. If we had given user2
new
ByteArray
values for both email
and username
, and thus only used the
active
and sign_in_count
values from user1
, then user1
would still be
valid after creating user2
. Both active
and sign_in_count
are types that
implement the Copy
trait, so the behavior we discussed in the "Copy
Trait" section would apply.